5(x^2+y^2+1)=6x+8y

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Solution for 5(x^2+y^2+1)=6x+8y equation:


Simplifying
5(x2 + y2 + 1) = 6x + 8y

Reorder the terms:
5(1 + x2 + y2) = 6x + 8y
(1 * 5 + x2 * 5 + y2 * 5) = 6x + 8y
(5 + 5x2 + 5y2) = 6x + 8y

Solving
5 + 5x2 + 5y2 = 6x + 8y

Solving for variable 'x'.

Reorder the terms:
5 + -6x + 5x2 + -8y + 5y2 = 6x + 8y + -6x + -8y

Reorder the terms:
5 + -6x + 5x2 + -8y + 5y2 = 6x + -6x + 8y + -8y

Combine like terms: 6x + -6x = 0
5 + -6x + 5x2 + -8y + 5y2 = 0 + 8y + -8y
5 + -6x + 5x2 + -8y + 5y2 = 8y + -8y

Combine like terms: 8y + -8y = 0
5 + -6x + 5x2 + -8y + 5y2 = 0

The solution to this equation could not be determined.

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